Question

A capacitor of capacitance C is given a charge go. At time t = 0, it is connected to a battery of emf E through a resistance R. Find the charge on the capacitor at time t.

Answer 1

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Answer 2

Thus the charge on the capacitor is q = EC(1 − e − tτC) + q0e − tτC)

Explanation:

Given data:

• Capacitance of capacitor = C
• Time "t" = 0

Solution:

qi=q0

qf=EC

Now, charge on capacitor change from qi to qf exponentially.

q = q0 + (EC − q0)(1 − e − 1τC)  

q = EC(1 − e − tτC) + q0e − tτC)

Here τC=CR

Thus the charge on the capacitor is q = EC(1 − e − tτC) + q0e − tτC)