Question

A capacitor of capacitance C is given a charge Q. At t = 0, it is connected to an ideal battery of emf ε through a resistance R. Find the charge on the capacitor at time t.

Answer 1

Thus the charge on the capacitor is q = EC(1 − e − tτC) + q0e − tτC)

Explanation:

Data given:

Capacitance of capacitor = C

Time "t" = 0

Solution:

qi=q0

qf=EC

Now, charge on capacitor change from qi to qf exponentially.

q = q0 + (EC − q0)(1 − e − 1τC)  

q = EC(1 − e − tτC) + q0e − tτC)

Here τC=CR

Thus the charge on the capacitor is q = EC(1 − e − tτC) + q0e − tτC)

Answer 2

Square Loop Moving Through Magnetic Field . ... The induced emf ε in a coil is proportional to the negative of the rate of change of ... Particles with charge inside experience a magnetic force. 0 q >. B q. = ×. F v. G