Physics, asked by kshitij346, 2 months ago

A capacitor of capacitance C1 = 1 uF is charged to a
potential of 100 V, the charging battery is then removed
and it is connected to another capacitor of
capacitance C2 = 2 pF in parallel. The charges on C1
and C2 in steady state are

100
200
,
-uc
3 HC
3
50 μC, 50 μο
100 μC, Ο
Zero, zero​

Answers

Answered by NewGeneEinstein
2

Answer:-

Case-1:-

  • Voltage=V=100V
  • Capacitance=C1=1uF
  • Charge=Q=?

\boxed{\sf Q=CV}

\\ \sf\longmapsto Q=100\times 1

\\ \sf\longmapsto Q=100C

Case-2:-

  • Voltage=V=100V
  • Capacitance=C2=2uF
  • Charge=Q=?

\\ \sf\longmapsto Q=CV

\\ \sf\longmapsto Q=100\times 2

\\ \sf\longmapsto Q=200C

Similar questions