A capacitor of capacitance C1 = 1 uF is charged to a
potential of 100 V, the charging battery is then removed
and it is connected to another capacitor of
capacitance C2 = 2 pF in parallel. The charges on C1
and C2 in steady state are
100
200
,
-uc
3 HC
3
50 μC, 50 μο
100 μC, Ο
Zero, zero
Answers
Answered by
2
Answer:-
Case-1:-
- Voltage=V=100V
- Capacitance=C1=1uF
- Charge=Q=?
Case-2:-
- Voltage=V=100V
- Capacitance=C2=2uF
- Charge=Q=?
Similar questions