Question

A capacitor of capacitance c1 is charged to a potential v1 while another capacitor of capacitance c2 is charged to a potential difference v2. The capacitors are now disconnected from their respective charging batteries and connected in parallel to each other. (a) find the total energy stored in the two capacitors before they are connected

Answer 1

Answer:

Initial total energy of two capacitors is

$U = \frac{1}{2}C_1V_1^2 + \frac{1}{2}C_2V_2^2$

Explanation:

As we know that the energy stored between the plates of capacitor is given as

$U = \frac{1}{2}CV^2$

here we know that the two capacitors are connected to two different batteries

so initial total energy of two capacitors is given as

$U = U_1 + U_2$

here we know

$U_1 = \frac{1}{2}C_1V_1^2$

$U_2 = \frac{1}{2}C_2V_2^2$

now from above equation initial total energy is

$U = \frac{1}{2}C_1V_1^2 + \frac{1}{2}C_2V_2^2$

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Topic : Energy stored in capacitor

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