Question

. A capacitor of capacity of 0.25 uF is discharged through an inductance of 10 mH
Calculate the frequency of discharge​

Answer 1

Explanation:

Given,

C=0.25uF=0.25×10^-6F

L=10mH=10×10^-3=10^-2

we have to calculate frequency(f)

f = 1/2π√LC

f = 1/2×3.14×√0.25×10^-8

f = 1/6.28×0.5×0.0001

f = 1/0.000314

f = 3.18×10^3

all steps are correct once check the calculation

Hope it helps you