a capacitor of unknown value and an indicator of 0.1 H and resistor of 10 ohm are connected in series to a 220V, 50Hz ac source. It is found that the power factor of circuit is unity. Calculate the capacitance of capacitor and maximum amplitude of current..
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From the given data:
L=0.1H
R=10
Power factor i.e cos∅=1, cos∅=R/Z (Z=impedance)
therefore, 1=10/z
z=10ΩΩ.
XL(inductive reactance= ωL
=2πfL= 10π≈ 31.4Ω
Z=√R²+(XL-XC)²
sub. all the values
You will get Capacitance ∵ XC as 98.5mC
I= V/R
=220/10
=22A
Hope it was helpful
Regards
MANSHI
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