Question

A capacitor when filled with a dielectric of dielectric constant = 3 has charge Q, voltage V, and electric

field E. If the dielectric is replaced with another one having = 9, the new value of charge, voltage and

field in the capacitor will be respectively​

Answer 1

Answer:

k(bddnekebbxksnwnn nkkdcnbendmsnsory

Answer 2

Answer:

E0/3

Explanation:

When there is no battery, charge remains same while potetnial difference and electric filed decreases

Q' = Q0

V'=V0 X 3 /9= V0/3

E'=E0 X 3/ 9=E0/3

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