Social Sciences, asked by dilavanya, 2 months ago

A Capacitors charged completely with a battery of Emf e now, it is disConnected and then connected to
battery of emf 2e. find Heat dissipated?​

Answers

Answered by singh639
0

Answer:

A capacitor of capacitance C is charged by connecting it to a battery of emf epsilon. The capacitor is now disconnected and reconnected to the battery with the polarity reversed. ... Thus, the work done by the battery appears as heat in the connecting wires. The heat produced is, therfore, 2C epsilon^2.

Explanation:

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