A capillary tube has a diameter of 0.06 mm inserted into the water with a contact angle of 45 degrees on the surface tension level of 0.05 N / m, then the water level in the capillary tube is ....
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d = 0.06 mm → r = 0.03 mm = 3×10^-5 m
θ = 45°
γ = 0.05 N/m
ρ = 10³ kg/m³
g = 10 m/s²
h = __?
Surface rise in capillary pipes
h = 2 γ cos θ / (ρ g r)
h = 2 • 0.05 • ½√2 / (10³ • 10 • 3×10^-5)
h = 0.2357 m = 23.56 cm
θ = 45°
γ = 0.05 N/m
ρ = 10³ kg/m³
g = 10 m/s²
h = __?
Surface rise in capillary pipes
h = 2 γ cos θ / (ρ g r)
h = 2 • 0.05 • ½√2 / (10³ • 10 • 3×10^-5)
h = 0.2357 m = 23.56 cm
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