Question

A capillary tube of internal radius 2 x 10-3m immersed vertically in a beaker containing a liquid. If the weight of the liquid rising inthe capillary tube is 9 x 10-5kg, the surface tension of liquid is​

Answer 1

Explanation:

Given A capillary tube of internal radius 2 x 10-3 m immersed vertically in a beaker containing a liquid. If the weight of the liquid rising in the capillary tube is 9 x 10-5 kg, the surface tension of liquid is

• Given internal radius of capillary tube r = 2 x 10^- 3 m
• So we have F = v ρ g  
•                          = 9 x 10^-5 kg
• Now surface tension T = F / 2 π r
•                              = 9 x 10^-5 / 2 x π x 2 x 10^-3
•                              = 0.00716 kg / m
• Now 1 kg/m = 9.806 N/m
• So 0.00716 kg/m = 0.00716 x 9,806
•                                = 0.0702 N/m
•                              = 7 x 10 ^-2 N/m

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https://brainly.in/question/14242682