Question

A capillary tube of radius 0·20 mm is dipped vertically
in water. Find the height of the water column raised in
the tube. Surface tension of water = 0.075 Nm" and
density of water = 1000 kg m". Take g = 10 m s.​

Answer 1

Answer:

We have,

$h = \frac{2s \cos( \alpha ) }{rg \times density}$

$= > \frac{2 \times 0.075 \times 1}{(0.20x {10}^{ - 3}) \times (1000)(10) }$

$= > 0.075m = 7.5cm$

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Answer 2

We have,

h =$\frac{2s \cos( \alpha ) }{rg \times density}$

h= rg×density2scos(α)

= > $\frac{2 \times 0.075 \times 1}{(0.20x {10}^{ - 3}) \times (1000)(10) }$

= > 0.075m = 7.5cm=>0.075m=7.5cm

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