Question

A capillary tube of radius 0.50 mm is dipped vertically in a pot of water. Find the difference between the pressure of the water in the tube 5.0 cm below the surface and the atmospheric pressure. Surface tension of water = 0.075 N m−1.

Answer 1

The difference between the pressure of the water in the tube is 190 N/m².

Explanation:

Given that,

Radius = 0.50 mm

Height = 5.0 cm

Surface tension = 0.075 Nm⁻¹

We need to calculate the excess pressure at 5 cm before the surface

Using formula of pressure

$P'=\rho\times g\times h$

$P'=1000\times5.0\times10^{-2}\times9.8$

$P'=490\ N/m^2$

Again excess pressure at the surface

$P''=\dfrac{2T}{r}$

$P''=\dfrac{2\times0.075}{5\times10^{-4}}$

$P''=300\ N/m^2$

We need to calculate the difference between the pressure of the water in the tube

$P=P'-P''$

$P=490-300$

$P=190\ N/m^2$

Hence, The difference between the pressure of the water in the tube is 190 N/m².

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Topic : difference the pressure

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