Question

A capillary tube of small radius is lowered into a liquid. Due to surface tension liquid rises in the capillary. If angle of contact is zero, then find the percentage of energy loss in the process.​

Answer 1

Answer:

Wood due to Surface Tension

d Theta= int6* dA

I / V = 6A

W = T * 2 * pi * r * R

T * cos theta * 2 * pi * r = weiglt of liquid

Tx * cos theta * 2 * pi * r = pvg

T * cos theta * 2 * pi * r = pvg T * 2 * pi * r = p*pi * r ^ 2 * h * q

h = 2T p* r+g

w=Tr partial pi* 2 tau prssg = 4 pi tau^ 2 prg

|n!= 4s pi* t^ 2 p* g

.. option (B) is correct.

Answer 2

Answer: $\frac{4\pi T^{2} }{pg}$

Surface tension:

When the surface of one liquid rubs against the surface of another, surface tension is said to occur (it can be a liquid as well). Liquids frequently have the smallest surface areas. An elastic sheet-like surface is how the liquid behaves.

Surface tension is influenced by the forces of attraction of the solid, liquid, or gas in contact with the supplied liquid as well as the forces of attraction between the particles in the liquid. The effort or energy necessary to remove the surface layer of molecules in a unit area can be conceived of as being roughly equal to the energy responsible for the phenomena of surface tension.

Explanation:

Work due to surface tension
$W=T$×$2\pi$×$r$×$h$

$Tcos$Θ×$2\pi r$$=$ weight of liquid raised

$T$×$cos$Θ×$2\pi r$$=$$pvg$

$T$×$cos$Θ×$2\pi r$$=$$p$×$v$×$g$

$T$×$cos$Θ×$2\pi r$$=$$p$×$\pi r^{2}h$×$g$

$h=\frac{2T}{prg}$

$W=T$×$2\pi r$×$\frac{2T}{prg}=\frac{4rT^{2}}{pg}$

$W=\frac{4rT^{2} }{pg}$

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