Question

A capillary tube whose inside is 0.5mm is dipped in water of surface tension 75 dyne/cm. Find the height of rise of water above the normal level​

Answer 1

Rise of a liquid in a capillary tube,

h=rρg2Scosθ

Here, r=0.07cm=0.07×10−2m

For water, S=0.07×Nm−1,ρ=103kgm−3

Angle of contact θ=0o

∴h=(0.007×10−2m)(103kgm−3)(10ms−2)2×(0.07Nm−1)×1

   h=2×10−2m=2cm