Question

A capillirity tube of radius r can support a liquid of weight 0.000628 N. If surface tension of liquid is 0.05 N/m then value of r is ?

Answer 1

T=F/H

H=F/T

H=(6.28 x 10^-4)/(5 x 10^-2)

H=1.256 x 10^-2m

H=2T/Rdg

d=M/V

H=2TV/RMg

Mg=6.28 x 10^-4

V=(pi)(R^2)H

1=2T(pi)R/Mg

R=(6.28 x 10^-4)/(2 x 5 x 10^-2 x 3.14)

R=2.0 x 10^-3m.