Question

A car a is moving with a speed of 40 km/h and car b is moving with a speed of 60 km/h along a parallel straight paths, starting from the same point. what is the position of car a w.r.t. b after 15 minutes?

Answer 1

This will help you a lot

Answer 2

Answer:

The car b is 5 km ahead of car a after 15 minutes.

Explanation:

Given that,

Speed of car a $v_{a}=40\ km/h$

Speed of car b $v_{b}=60\ km/h$

Time t = 15 min= 0.25 h

The distance traveled by the cars is related to the time and their respective velocities as:

$v_{a}=\dfrac{d_{a}}{t}$

For car a,

$d_{a}=40\times0.25$

$d_{a}=10\ km$

For car b,

$d_{b}=60\times0.25$

$d_{b}=15\ km$

The distance between car a and car b is

$d=d_{b}-d_{a}$

$d =15-10$

$d = 5\ km$

Hence, The car b is 5 km ahead of car a after 15 minutes.