Physics, asked by Adi19372827, 8 months ago

a car a is travelling on a straight level road with a speed of 54km/hr it is followed by another car b which is moving with a speed of 72 km/h. when the distance between them is 5km the car driver of car b accelerates his car at the rate of 40 km/h.what distance and time will car B just catch up with car a

Answers

Answered by Ramorrc31
4

Answer:

car b will catch up the car a at the distance of 7.4 km in 3.9 minutes.

Explanation:

the difference between the speed of both the cars are 18 km/ hr and 5km in terms of distance.

car b accelerate by 40km/hr

the speed of car b = 72+40 =112km/hr

to catch up car a , car b has to cover up the distance of 5 km

time = distance / speed

time = 5000 m / 31 m/s

time = 161 seconds = 2.6 minutes

now,

car a is also travelling at 54km/hr

so, car a will travel

distance = speed x time

distance = 15m/s x 161 s

distance = 2415m = 2.4 km

now.

to catch up car a , car b has to cover up the distance of 5+2.4=7.4 km

time = distance / speed

time = 7400 m /  31m/s

time = 239 seconds = 3.9 minutes

therefore, car b will catch up the car a at the distance of 7.4 km in 3.9 minutes.

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