Physics, asked by hrahmanFatima4311, 6 months ago

A car A leaves city x at t = 0 and moves with constant speed 40 kmh−1 due West. Another car B leaves 12h later from city y, which is 30 km South-West of x and moves with constant speed 20√2 kmh−1 North-West. Find minimum separation and between them and time when they are at this minimum separation

Answers

Answered by tanuraval2821
0

Answer:

both a and b

the minimum separation of car is 20 km

they are at minimum separation at t=1/2√2 h

Answered by anvitanvar032
0

Answer:

The correct answer of this question is \frac{6 +2 \sqrt{2} }{2\sqrt{2} }

Explanation:

Given - A car A leaves city x at t = 0 and moves with constant speed 40 kmh−1 due West. Another car B leaves 12h later from city y, which is 30 km South-West of x and moves with constant speed 20√2 kmh−1 North-West.

To Find - Find minimum separation and between them and time when they are at this minimum separation.

The minimum separation of cars is 20 kmh-1

They are at minimum separation at t = 1/( 2√2) h

Minimum separation is 20 × 1

Time of minimum separation \frac{6 +2 \sqrt{2} }{2\sqrt{2} }

#SPJ2

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