Question

a car a of mass 1500kg traveling at 25m/s collides with car b of mass 1000kg travelling at 15 m/s in the same direction after collision the velocity of cara become 20m/s calculate the velocity of car b after collision​

Answer 1

Answer:

22.5m/s

Explanation:

momentum of car A before collision=1500*25 eq1

momentum of car B before collision=1000*15 eq2

momentum of car A after collision=1500*20 eq3

momentum of car B after collision 1000*v eq4

using law of conservation of total linear momentum

eq1+eq2=eq3+eq4

52500=30000+1000v

22500=1000v

v=22.5m/s

Answer 2

${\underline {\underline {\Large {\bf { Provided \: Question: } }}}}$

A car of mass 1500kg traveling at 25m/s collides with car B of mass 1000kg travelling at 15 m/s in the same direction after collision the velocity of car A become 20m/s.Calculate the velocity of car B after collision.

${\underline {\underline {\Large {\bf { Required \: Answers: } }}}}$

As per the provided question, we have:

Before collision:–

• Mass of the car A = 1500 kg
• Velocity of the car A = 25 m/s
• Mass of the car B = 1000 kg
• Velocity of the car B = 15 m/s

After collision:–

• Velocity of car A becomes 20 m/s.

To calculate:

• Velocity of car B after collision.

Calculation:

Firstly we have to calculate the momentum of the both objects before and after collision,in order to solve this problem.

${\underline {\boxed {\Large {\bf { Before \: Collision:– } }}}}$

• Momentum of car A = Mass of the of the car × Velocity of the car

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$\bf { ⇢Momentum \: of \: car \: A= 1500 \times 25 }$⠀⠀

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$\bf { ⇢Momentum \: of \: car \: A = 37,500 \: kg.m/s}$

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• Momentum of car B= Mass of the of the car × Velocity of the car

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$\bf { ⇢Momentum \: of \: car \: B= 1000 \times 15}$⠀⠀

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$\bf { ⇢Momentum \: of \: car \: B = 15000 \: kg.m/s}$

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• Total momentum of Car A and car B= 37,500 + 15,000= 52,500kg.m/s⠀(Before collision)........ $\rm {(1) }$

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${\underline {\boxed {\Large {\bf { After \: Collision:– } }}}}$

As per the given question, Velocity of the first object becomes 3m/s after the collision, So

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• Momentum of car A = Mass of the car Velocity of the car

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$\bf { ⇢Momentum \: of \: car \: A = 1500 \times 20 }$⠀⠀

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$\bf { ⇢Momentum \: of \: car \: A= 30,000kg.m/s}</p><p></p><p>Now, let's assume the velocity of 2nd object as<strong> v </strong>m/s after collision. So,</p><p>⠀⠀⠀</p><p></p><ul><li><strong><u>Momentum of car B</u></strong> = Mass of the of the car × Velocity of the car</li></ul><p>⠀⠀</p><p></p><p>[tex] \bf { ⇢Momentum \: of \: car \: B = 1000 \times v }$

⠀⠀

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$\bf { ⇢Momentum \: of \: car \: B = 1000v \: kg.m/s}$

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• Total momentum of both cars = 30,000+ 1000v kg.m/s ⠀⠀⠀(After collision).........$\rm {(2)}$

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According to the law of conservation of momentum:

${\underline {\boxed {\small {\tt { {Total \: momentum}_{(Before \: collision) } = {Total \: momentum}_{(After \: collision) } } }}}}$

It means,

$\bf { ⇢52, 500= 30,000 + 1000v }$⠀⠀

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$\bf { ⇢1000v = 52500 -30000}$⠀⠀

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$\bf { ⇢1000v = 22500}$

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$\bf { ⇢v = \dfrac{22500}{1000} }$

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$\boxed { \bf { ⇢v = 22.5m/s} }$

Therefore, the velocity of the car B after collision is 22.5m/s.

$\rm \blue { So, we \: are \: done!! }$

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