a car accelarates uniformly from 18km/h to 54 km/h in 5 second. calculate the acceleration
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Answer
- Acceleration , a = 2 m/s²
Given
- a car accelerates uniformly from 18 km/h to 54 km/h in 5 second
To Find
- Acceleration
Solution
Initial velocity , u = 18 km/h = 18 * ( 5/18 ) = 5 m/s
Final velocity , v = 54 km/h = 54 * ( 5/18 ) = 15 m/s
Time , t = 5 s
Change in velocity , v - u = 10 m/h
We know that , " Acceleration is defined as rate of change of velocity "
⇒ Acceleration , a = ( v - u ) / t
⇒ a = 10 / 5
⇒ a = 2 m/s²
Answered by
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GivEn :-
- A Car accelerates Uniformly from 18km/h to 54km/h in 5 seconds
To FinD :-
- The Acceleration of the Car
SoluTioN :-
We Are Given with quantities
• Initial Velocity u = 18 km/h = 18*5/18 = 5m/s
• Final Velocity v = 54 km/h = 54*5/18 = 15 m/s
• Time taken t = 2 seconds
We Converted Km/h to m/s because SI unit is m/s
- Acceleration a = change in Velocity / time
- a = v - u / t
- a = 15-5/2
Hence Acceleration a = 2m/s2
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