Question

A car accelerares uniformly from 18km/h to 36km/h in 5s. Calculate (1) the acceleration and (2) the distance covered by the car in that time.

Answer 1

Hope this will help you

Answer 2

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We are given that

$u = 18 \: km \: h^{ - 1} = 5 \: m \: s ^{ - 1}$

$v = 36 \: km \: h^{ - 1} = 10 \: m \: s^{ - 1} and \:$

$t = 5 \: s.$

$1) \: we \: have$

$a = \frac{v - u}{t}$

$\frac{10cm \: s^{ - 1} - 5m \: s^{ - 1} }{5s}$

$= 1 \: \: m \: s^{ - 2}$

$2)we \: have \:$

$s = u \: t + \frac{1}{2} \: a \: t^{2}$

$= 5m \: s^{ - 1}\times 5 \: s + \frac{1}{2} \times 1m \: s^{ - 2} \times (5s)^{2}$

$=25 \: m + 12.5 \: m$

$= 37.5 \: m$

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