A car accelerate at 1.5 m/s2 in a straight road . how much is the increase in velocity in 4 s?
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Explanation:
We can solve this problem by using the formula :
v=u+ at
where -
v is the final velocity acquired
u is the initial velocity
a is the acceleration
t is the time taken by the car
Now, in our problem, the car accelerates at 1.5m/s^2 for 4 seconds. That gives us a final velocity v of u+(4×1.5) which is u+6 m/s. So our increase in velocity is 6m/s. The straight road part tells us that the direction remains constant. Hence the velocity vector changes only in magnitude.
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