Question

A car accelerate at 1.5m/s2 in a straight road. how much is the increase in velocity in 4s​

Answer 1

${\mathfrak{Solution:-}}$

★ ${\mathtt{\underline{Given:-}}}$

$\sf{a = 1.5\;m/sec^{2}}$

$\sf{t = 4\;sec}$

$\sf{v=at}$

$\sf{= 1.5\times 4}$

$\sf{=6\;m/s}$

Answer 2

6 m/s

Explanation:

Given,

Acceleration,a= 1.5 m/s^2

Time taken,t= 4 seconds

Initial velocity,u= 0

Final velocity,v = ?

Therefore,

v=u+at

v=0+1.5x4

v=1.5x2

v=6 m/s

Hope it is helpful