A car accelerate from 6 m./ s. to 16 m./s. in 10 seconds . Calculate - 1. the acceleration 2. the distance covered.
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1. acceleration
given, u=6m/s v=16m/s t=10sec
using first equation of motion
v=u+at then a=v-u/t
=16-6/10= 1m/sec2
2. distance
given, u=6 t=10 a=1
using second equation of motion
s=ut+1/2at square = 6×10+1/2×1×10×10
=110m
given, u=6m/s v=16m/s t=10sec
using first equation of motion
v=u+at then a=v-u/t
=16-6/10= 1m/sec2
2. distance
given, u=6 t=10 a=1
using second equation of motion
s=ut+1/2at square = 6×10+1/2×1×10×10
=110m
Shobhitrai:
Thank you
It is correct
my pleasure
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