Question

A car accelerate from rest at the constant rate of 2m/s2 for Some Time. Then it retards at constant rate of 4m/s2 and Comes at rest
if it remain in motion for 3 sec then what is Distance covered by car​

Answer 1

Answer

data given;

initial velocity=2m/s2

final velocity=4m/s2

time taken by the car=3 sec

find the distance covered by car=?

        apply this formula

s=ut + 1/2at2

s=2m/s2 . 3 sec + 1/2 . 4m/s2 . 3 .3

s=6+18

s=24

therefore; the distance covered by car is 24m

 i think it may help u

Explanation: