a car accelerate on a straight road from rest to a speed 180 km per hour in 25 s assuming uniform acceleration of car through out what is the distance covered in this time?
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Hey
distance (s) =?
v^2 = u^2 + 2 as
a =?
a = v - u / t ; v = 50 m/s
= 50 - 0/ 25
= 50/25 = 2 m/s^2
v^2 = u^2 + 2 as
50^2 = 0^2 + 2 × 2 × s
2500 = 0 + 4s
4s = 2500
s = 2500/4
distance = 625 m
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Hope this helps!
distance (s) =?
v^2 = u^2 + 2 as
a =?
a = v - u / t ; v = 50 m/s
= 50 - 0/ 25
= 50/25 = 2 m/s^2
v^2 = u^2 + 2 as
50^2 = 0^2 + 2 × 2 × s
2500 = 0 + 4s
4s = 2500
s = 2500/4
distance = 625 m
========================================================
Hope this helps!
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