Question

a car accelerate s uniformly from 18 km/h tob36 km/h in 5 second. calculate (i) the acceleration and(ii) the distance covered by the car in that time​

Answer 1

Distance = 5m

And acceleration in m\s =

a(1) = 5m\s

a(2) = 10 m\s

Answer 2

• What is Acceleration...???

• Change in the velocity of an object per unit time.

• Acceleration a = v-u/t

• S.I Unit : m/s²

• Here, u = initial velocity and v = final velocity.

         a = acceleration and t = time.

i) u = 20 km/h = 5.5 m/s

 v = 35 km/h = 9.7.. m/s

 t  =  5 second

 a = v-u/t

 a = 9.7 - 5.5 / 5

 a = 4.2 / 5

 a = 0.84 m/s²

ii) The Distance covered :

   s = ut + 1/2 at²

   Here, s = distance travelled by the object.

         t = time

         a = uniform acceleration.

         s = 5.5 × 5 + 1/2 ( 0.84 ) ( 5 )²

         s = 27.5 + 1/2 × 0.84 × 25

         s = 27.5 + 10.5

         s =  38m.