Question

A car accelerate uniform from 54km/h to 108km/h in 10 second. calculate the acceleration.
please solve the question
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Answer 1

Answer:

acceleration=

2.85m/s^2

Answer 2

Answer:

54 km/h = 54 × 5/18 = 15 m/s (Converting speed in m/s)

Similarly, 108km/h = 108 × 5/18 = 30 m/s.( '' '' )

As we know that acceleration is the rate of change of velocity..

So here, 'a' = (30-15)/10

a = 15/10 ⇒ a = 1.5 m/$s^{2}$

Now,

       We know that, by 3rd equation of motion,

         $v^{2}$ - $u^{2}$ = $2as$

Here,  v = 30m/s

          u = 15 m/s

and     a= 1.5 m/$s^{2}$

So,

$(30)^{2}$ - $(15)^{2}$ = 2 × 1.5 × $s$

900 - 225 = 3 × $s$  ⇒ 675 = 3 ×

675 = 3 × $s$  ⇒

$s$ = 225 m

Therefore, distance travelled is 225m and acceleration is 1.5 m/$s^{2}$

Hope it helps you

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