Question

A car accelerate uniformly by 1m/s from 5m/s to 10m/s in 5s calculate the distance covered by the car in that time​

Answer 1

Answer:

So car covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s.

Explanation:

Answer 2

$\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}$

A car accelerate uniformly by 1 $\sf m {s}^{ - 2}$ from 5 m/s to 10 m/s in 5 s . Calculate the distance covered by the car in that time .

$\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}$

• Distance Covered by car = 37.5 m

$\huge\purple{ \underline{ \boxed{\mathbb{\red{EXPLANATION : }}}}}$

$\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}$

• Initial velocity ( u ) = 5 m/s

• Final velocity ( v ) = 10 m/s

• Time taken ( t ) = 5 s

• Acceleration ( a ) = 1 $\sf m {s}^{ - 2}$

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• Distance covered by the car.

$\green{ \large \underline{ \mathbb{\underline{ EQUATION \: OF \: MOTION \: USED : }}}}$

$\Large{ \purple{ \boxed{\begin{array}{l} \sf {v}^{2} - {u}^{2} = 2as \: \: \end{array}}}}$

$\green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}$

$\large{\purple{ \underline{\underline{\textsf{Distance Covered by car}}}}}$

$\: \: \displaystyle \sf \longrightarrow {v}^{2} - {u}^{2} = 2as \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow {(10)}^{2} - {(5)}^{2} = 2(1)s \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow 100 - 25 = 2s \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\\displaystyle \sf \longrightarrow 75 = 2s \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow 2s = 75 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow s = \frac{75}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow s = 37.5 \: m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\purple{\boxed{ \begin{array}{l} \textsf{Distance Covered by car = 37.5 m} \end{array}}}$

$\green{ \large \underline{ \mathbb{\underline{KNOW\:MORE: }}}}$

• Acceleration

Acceleration is the rate at which velocity changes with time .

• Initial Velocity

Initial velocity is the velocity of the object before the effect of acceleration .

• Final Velocity

Final velocity is the velocity of the object after the effect of acceleration .

• Distance

Distance is the length of actual path covered by a moving object in a given time interval .

$\Large{\purple{\boxed{\begin{array}{l} \textsf{Equations of motion : } \\ \\ \textsf{v = u + at} \\ \\ \displaystyle\textsf{s = ut + \sf\frac{1}{2}a {t}^{2} } \\ \\ \sf {v}^{2} - {u}^{2} = 2as \end{array}}}}$