A car accelerate uniformly from 18 km h-1to 36 km h-1in 5 sec. calculate the acceleration
Answers
Answered by
3
initial velocity (u) = 18km/h = 5m/s
final velocity (v) = 36km/h = 10m/s
time taken (t) = 5sec
acceleration = (v-u)/t = (10-5)/5 = 1 m/s²
final velocity (v) = 36km/h = 10m/s
time taken (t) = 5sec
acceleration = (v-u)/t = (10-5)/5 = 1 m/s²
Answered by
5
u = 18 km/h = 18×5/18 = 5 m/s
v = 36 km/h = 36×5/18 = 10 m/s
t = 5 sec
a = (v-u)/t
= (10-5)/5
= 5/5
= 1 m/s²
v = 36 km/h = 36×5/18 = 10 m/s
t = 5 sec
a = (v-u)/t
= (10-5)/5
= 5/5
= 1 m/s²
Anonymous:
I hope it will help you.
Similar questions