a car accelerate uniformly from 18 km/h to 36 km/h in 5 sec. calculate the distance covered by carin that time
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but correct answer is 37.5 meter
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U=18km/h
U= 18×1000/60×60
U=5 m/sec
V= 36×1000/60×60
V= 10m/sec
t= 5 sec
V=U+at
10=5+a×5
a×5=5
a= 5/5
a= 1m/sec²
S=Ut+1/2at²
S= 5×5+ 1/2× 1× (5)²
S= 25+ 12.5
S=37.5m
Hope good luck
U= 18×1000/60×60
U=5 m/sec
V= 36×1000/60×60
V= 10m/sec
t= 5 sec
V=U+at
10=5+a×5
a×5=5
a= 5/5
a= 1m/sec²
S=Ut+1/2at²
S= 5×5+ 1/2× 1× (5)²
S= 25+ 12.5
S=37.5m
Hope good luck
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