a car accelerate uniformly from 18 km\h to 36 m\s in 5 S. calculate acceleration and distance
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Acceleration = 1 m/s-2 distance = 37.5
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u = 18 kmph
v = 36 kmph
t = 5 s
a = (v -u) / t
= (36-18) / 5
= 3.6 m/s
s = (v +u ) / 2 *t
= (18+36)/2 *5
=135 meters ....
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v = 36 kmph
t = 5 s
a = (v -u) / t
= (36-18) / 5
= 3.6 m/s
s = (v +u ) / 2 *t
= (18+36)/2 *5
=135 meters ....
I hope you like answer soo plzz mark as brainliest answer and click on red heart button..... :-)
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