A car accelerate uniformly from 18kmh-1 to 36kmh-1 in 5 second calculate the acceleration and distance covered by the car in that time
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3
acceleration=1m/s2
d=75/2m
d=75/2m
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4
Initial velocity = 18km/hr =5m/sec.
Final velocity = 36 km/hr = 10m/sec.
a =(v -u )/ t
= 10msec - 5msec / 5 = 1 m /sec-2 .
Distance = v2 - u2 /2a .
= 100 /2 = 50m
Final velocity = 36 km/hr = 10m/sec.
a =(v -u )/ t
= 10msec - 5msec / 5 = 1 m /sec-2 .
Distance = v2 - u2 /2a .
= 100 /2 = 50m
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