a car accelerate uniformly from 18kmh-1 to 36kmh-1 in 5s calculate acceleration,distance covered by the car in that time
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a car accelerate uniformly from 18kmh-1 to 36kmh-1 in 5s calculate acceleration,distance covered by the car in that time
u = 18km/hr = 5 m/s
v = 36km/hr = 10m/s
t = 5 s
a = v-u/t
= 10 - 5/5
= 5/5 = 1 m/s²
s = ut + 1/2 at²
= 5 x 5 + 1/2 x 1 x 5 x 5
= 25 + 25/2
= 50 + 25 /2
= 75/2 = 37.5 m
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