A car accelerate uniformly from 36 km/h to 72 km /h in 10 seconds. Calculate a.theacceleraionb. the distance covered by the car in that time
Answers
Answered by
0
On converting 36km/h in m/s we get u= 10m/s
And v=72km/h=20 m/s
Now a=v-u/t
=20-10/10
=1 m/s
Distance covered=
s=ut+½at²
=10×10+½×1(10)²
=150 m
Similar questions