a car accelerated from 10 kilometre per hour to 40 kilometre per hour into minutes how much distance does it cover in this period (assume that the path is straight)
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Initial velocity of car (u) = 10km/hr
final velocity of car(v) = 40 km/hr
Time taken(t) = 1minutes = 1/60hr
Acceleration of the car(a) = v - u
t
= 40 -10
1/60
= 30 × 60 = 1800km/hr²
Now, using Equation v² = u²+2as
(40)²= (10)²+2×1800×s
1600-100 = 3600s
1500 = 3600s
s = 1500 = 5/12km
3600
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