Question

A car accelerated uniformly from (18 km/h
to 36 km 1h within a distance of 15 metre
The uniform acceleration of the car is​

Answer 1

Answer:

2.5 $m/s^{2}$

Explanation:

Initial speed($u$) = 18 km/h = $18 * \frac{5}{18} = 5 m/s$

Final speed($v$) = 36 km/h = $36 * \frac{5}{18} = 2 * 5 = 10 m/s$

Distance traveled($s$) = 15 m

Using 3rd equation of motion

$v^{2} = u^{2} + 2as\\10^{2} = 5^{2} + 2*a*15\\100 = 25 + 30a\\100 - 25 = 30a\\30a = 75\\a = \frac{75}{30} = \frac{25}{10} = 2.5 m/s^{2}$

Therefore

uniform acceleration is 2.5 $m/s^{2}$