Question

A car accelerated uniformly from 18 km/h to 36 km/h in 5 s. The acceleration in ms^-2 is what?

Answer 1

Answer:

Given

Initial velocity=18 km/hr = 5 m/s

Final velocity=v=36km/h=10 m/s

Time taken = 5 seconds

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v-u)/t

Substituting the given values in the above equation we get,

a=(10-5)/5 =5/5= 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a t2

Substituting the given values in the above equation we get,

S =5×5 + (1/2)×1×52

25 + (1/2) X 25

25 + 12.5

= 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m

Explanation:

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Answer 2

$\huge{ \red{ \pmb{ \underline{Given}}}}$

Initial velocity=18 km/hr = 5 m/s

Final velocity=v=36km/h=10 m/s

Time taken = 5 seconds

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v-u)/t

Substituting the given values in the above equation we get,

a=(10-5)/5 =5/5= 1 m/s2

We know that distance travelled is calculated by the formula

$\boxed{ \red{Distance \: travelled \: S = u t + (1/2) a t2}}$

Substituting the given values in the above equation we get,

$\ \: S =5×5 + (1/2)×1×52$

$\rightarrow{25 + (1/2) X 25}$

$\rightarrow \: {25 + 12.5}$

$\rightarrow \: {37.5 m}$

Hence

$\boxed{ \pmb{acceleration \: a =1 m/s2}}$

$\boxed{ \pmb{Distance \: travelled \: S =37.5 \: m}}$