Question

A car accelerated uniformly from 18 km/h to 36 km/h within a distance of 15 metre. The uniform acceleration of the car is

Answer 1

Answer:

Acceleration=

Time

Change in Velocity

Change in Velocity = 36−18=18km/h=5m/s

Time=5 Seconds

Acceleration =

5

5

=1m/s

2

Equation of motion can be given as:

s=ut+(

2

1

)at

2

u=18km/h=5m/s

t=5s

a=1m/s

2

s=(5×5)+(

2

1

×1×5×5)

s=25+12.5

s=37.5m

Answer 2

$\huge\blue{solution}$

formula for acceleration = ∆v/time;

where,v = velocity of car

and t = time period.

______________________________________

Given information:

initial velocity = 18 km/h = 5m/s

final velocity = 36km/h = 10m/s

time = 10+5 /15 = 1 s

______________________________________

acceleration = (10-5/1)m/s^2

5m/s^2

hope it helps you