A car accelerates 6 m/s to 18 m/s in 12 seconds. Assuming the acceleration to be uniform calculate
A) the acceleration and
B) the distance covered in 12 seconds.
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Answer:
a = 1m/s², distance = 144m
Explanation:
first,
v=u+at
= 18=6+a(12)
=18-6= a(12)
= 12/12 = a
= a = 1m/s² ans.
now,
v² = u²+2as
= (18)² = (6)²+2*1*s
= 324 = 36+2s
= 324-36 = 2s
= 288 / 2 = s
s = 144m ans.
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