A car accelerates at 1.5 m/s2 on a straight road. How much is the increase in velocity in the next 6 seconds?
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Answered by
6
supposing that it's initial velocity was u
using first equation of motion:
v = u + at
v = u + (1.5)(6)
v = u + 9
so,
the increase in the velocity would be u+ 9 where u is it's initial velocity
using first equation of motion:
v = u + at
v = u + (1.5)(6)
v = u + 9
so,
the increase in the velocity would be u+ 9 where u is it's initial velocity
siddhartharao77:
Good Explanation.
Answered by
0
Answer:
a = 1.5
u = 0
t = 6s
1.5 = v - 0 / 6
1.5 = v/6
v = 15/10 * 6
= 90/10
after cutting it will be 9 m/s
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