Question

A car accelerates at 1.5m/sce2 in a straight road .How much is the increase in the velocity in 4sec?

Answer 1

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✳A car accelerates at 1.5$\frac{m}{sec²}$ in a straight road. How much is the increase in the velocity in 4Sec?

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➡We can solve this problem by using the below given formula of acceleration

⭐v = u + at

Where,

➡v = final velocity acquired

➡u= initial velocity

➡a= acceleration

➡t= time taken by the car

Now, the car accelerates at 1.5$\frac{m}{sec²}$ for 4 seconds

➡That gives us a final velocity v of u +(4 X 1.5)

which is u+ 6$\frac{m}{s}$.

➡So increase in the the velocity is 6$\frac{m}{s}$

➡The straight road part tells us that the direction remains constant .

➡Hence, the velocity vector changes only magnitude.

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