Question

A car accelerates at 3 m/s/s, assuming it starts from rest, how much time does it take to accelerate to speed of 45 m/s?

Answer 1

Given:-

• Acceleration ,a = 3m/s²

• Initial velocity ,u = 0m/s

• Final velocity ,v = 45m/s

To Find:-

• Time ,t

Solution:-

By using 1st equation of motion

• v = u+at

Substitute the value we get

→ 45 = 0 + 3 ×t

→ 45 = 3×t

→ t = 45/3

→ t = 15s

Therefore ,the time taken by the car is 15 seconds

Additional Information !!

Some equation of motion are

• v = u +at

• s = ut +1/2at².

• v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

Answer 2

Answer:

• Time taken by the car = 15 seconds

Given:

• The given acceleration is 3m/s².
• The given Initial velocity is 0m/s.
• The given final velocity is 45m/s.

Need to find:

• Time taken by the car = ?

Solution:

According to the first equation of motion:

• v = u + at

Putting the values:

➦ 45 = 0 + 3 × time

➦ 45 = 3 × time

➦ Time = 45/3

➦ Time = 15 seconds

Therefore:

• Time taken by the car = 15 seconds

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