Question

A car accelerates at 9.76ms-2 for a time of 4s. It reaches a speed of 52ms-1. Calculate the initial velocity.

Answer 1

Answer:

12.96m/s^-1

Explanation:

v=u+at

52=u+9.76(4)

u=52-39.04

u=12.96m/s^-1

Answer 2

Answer:

12.96ms^-1

Explanation:

given that

acceleration =9.76ms^-2

time taken =4seconds

final velocity =52ms^-1

let initial velocity = u ms^-1

using equation of motion

v=u+at

52=u+9.76×4

52=u+39.04

u=52.00-39.04

u=12.96ms^-1

hope you understand