Physics, asked by yabiserab, 2 months ago

A car accelerates at a speed of 40m/s is accelerated uniformly to a speed of 60m/s in 4 second .The distance covered in 2 second

Answers

Answered by nikita6777
0

Answer:

90m

Explanation:

initially velocity was 40m/s

final velocity is 60m/s

Time taken for the change is 4sec

so acceleration is

a = v-u/t

= 60- 40/4

= 20/4 = 5

distance covered is

s = ut + 1/2 at²

= 40×2 + 1/2×5×(2)²

= 90m

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