A car accelerates at a speed of 40m/s is accelerated uniformly to a speed of 60m/s in 4 second .The distance covered in 2 second
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Answer:
90m
Explanation:
initially velocity was 40m/s
final velocity is 60m/s
Time taken for the change is 4sec
so acceleration is
a = v-u/t
= 60- 40/4
= 20/4 = 5
distance covered is
s = ut + 1/2 at²
= 40×2 + 1/2×5×(2)²
= 90m
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