a car accelerates for 6 Sec. the velocity of the car increase from 15m/s until the velocity is 2.8 m/s
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40 km southwest
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Correct Question:-
A car accelerates for 6 Sec. the velocity of the car increase from 15m/s until the velocity is 28 m/s.
Solution:-
Given,
- Car accelerates for 6sec and increase from 15m/s to 28m/s.
We can find the acceleration by using the first equation of motion:-
u = 15m/s ; v = 28m/s ; t = 6sec ; a = ?
➣ v = u + at
➣ 28 = 15 + 6a
➣ 28 - 15 = 6a
➣ 13 = 6a
➣ a = 13/6
➣ a = 2.16m/s²
We can find the distance by using the third equation of motion:-
➣ s = ut + 1/2 at²
➣ s = 15(6) + 1/2 * 2.16 * 6 * 6
➣ s = 90 + 2.16 * 6 * 3
➣ s = 90 + 38.88
➣ s = 128.88m
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