Question

a car accelerates from 10 m/s to 40 m/s in 6.0 s. how far did it travel in this time

Answer 1

Question:

A car accelerates from 10 m/s to 40 m/s in 6.0 s. How far did it travel in this time?

To-find:

Distance travelled by the car in accelerated-speed-time.

Answer:

$\Large{\boxed{\red{\underline{150 \: m}}}}$

Formula-used:

a = $\frac{v-u}{t}$

s = ut + $\frac{1}{2}$at$^{2}$

where, a = acceleration, s = distance, u = initial velocity, v = final velocity and t = time.

Explanation:

Given,

u = 10 m/s

v = 40 m/s

t = 6 s

a = ?

s = ?

First, we need to find acceleration, so,

a = $\frac{v-u}{t}$

a = $\frac{40-10}{6}$

a = $\frac{30}{6}$

a = 5 m/s$^{2}$

Now, after we have value of acceleration, we can find value of distance travelled.

so, we have, s = ut + $\frac{1}{2}$at$^{2}$

s = 10 × 6 + $\frac{1}{2}$ × 5 × 6$^{2}$

s = 10 × 6 + $\frac{1}{2}$ × 5 × 36

s = 60 + $\frac{1}{2}$ × 180

s = 60 + 90

s = 150 m

So, the distance travelled by car in the acceleration time is 150 m.

$\large{\boxed{\red{\underline{150 \: m}}}}$

Answer 2

Answer:

5m/s^2

Explanation:

a=v-u/10

a=40-10/6

a=30/6

a=5