A car accelerates from 18km/hr do 36km/hr in 10s. Calculate its acceleration in m/s2sq
Answers
Answered by
1
initial velocity = 18 km/hr = 5 m/s
final velocity = 36km/hr = 10 m/s
time = 10s
acceleration = (v-u)/t =(10-5)/10 = 5/10 = 0.5 m/s²
hope this helps
final velocity = 36km/hr = 10 m/s
time = 10s
acceleration = (v-u)/t =(10-5)/10 = 5/10 = 0.5 m/s²
hope this helps
Answered by
1
Heya
we know that
acceleration = ∆v/t
Here ☠v = 36-18 => 18km/hr
or 18×5/18=> 5m/s
so acceleration = 5/10 => 0.5 m/s²
we know that
acceleration = ∆v/t
Here ☠v = 36-18 => 18km/hr
or 18×5/18=> 5m/s
so acceleration = 5/10 => 0.5 m/s²
Similar questions