Question

a car accelerates from 18km/hr to 36 km/hr in 5 second,calculate it's acceleration ​

Answer 1

Answer:

$acceleration \: = \frac{final \: velocity \: - initial \: velocity}{time}$

$time \: = 5sec$

$inital \: velocity \:( u) \: = 18km/hr \\ 5m/sec$

$final \: velocity \: (v) = 36km/hr \\ 10m/sec$

$a = \frac{v - u}{t}$

$a = \frac{10 - 5}{5}$

$a = 1m/ {sec}^{2}$

Answer 2

Answer:

1m/s^2

Step-by-step explanation:

Given:

u = 18km/hr

v = 36km/hr

t = 5 sec

first we need to change km/hr into m/s

18km/hr =

$\frac{18 \times 1000}{60 \times 60} = \frac{18 \times 5}{18} = 5ms {}^{ - 1}$

36km/hr

$\frac{36 \times 5}{18} = 10ms {}^{ - 1}$

$a \: = \: \frac{v - u}{t}$

$a \: = \frac{10 - 5}{5} = \frac{5}{5} = 1ms {}^{ - 2}$

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