Question

A car accelerates from 36 km /h to 54 km/h in 10 sec . find the acceleration and distance travelled by car

Answer 1

Given:

Initial velocity= 36km/h=36x5/18=10m/s
Final velocity =54km/h=54x5/18=15m/s
Time =10sec
Acceleration = v-u/ t
=15-10/10=5/10=1/2=0.5 m/s2
Distance =s=?
From second equation of motion:
S=ut +1/2 at^2
=10*10+1/2*0.5*10*10
=100+25
=125m
So distance travelled is 125m

Answer 2

Explanation:

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